how does increasing the distance between charged objects affect the electric force between them?\nthe…

Brief Explanations:

According to Coulomb's law, the electric - force between two charged objects is inversely proportional to the square of the distance between them. That is, $F = k\frac{q_1q_2}{r^2}$, where $F$ is the electric force, $q_1$ and $q_2$ are the charges of the two objects, $r$ is the distance between them, and $k$ is a constant. As the distance $r$ increases, the denominator $r^2$ increases, and the value of the fraction $\frac{q_1q_2}{r^2}$ decreases, so the electric force $F$ decreases. The relationship between distance and force is an indirect (inverse) one.

Answer:

The electric force decreases because the distance has an indirect relationship to the force.