ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45° relative to the ground. the…

ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45° relative to the ground. the horizontal component of the initial velocity to the nearest tenth is m/s.

ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45° relative to the ground. the horizontal component of the initial velocity to the nearest tenth is m/s.

Answer

Explanation:

Step1: Recall velocity - component formula

The formula for the horizontal component of the initial velocity $v_{0x}$ is $v_{0x}=v_0\cos\theta$, where $v_0$ is the initial velocity and $\theta$ is the angle of projection.

Step2: Substitute given values

Given $v_0 = 12$ m/s and $\theta = 45^{\circ}$, and $\cos45^{\circ}=\frac{\sqrt{2}}{2}$. So $v_{0x}=12\times\cos45^{\circ}=12\times\frac{\sqrt{2}}{2}=6\sqrt{2}\approx 8.5$ m/s.

Answer:

$8.5$