the inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y. y =…

the inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y. y = 3×10^8 / x what are the wavelengths for x - rays with frequency 3×10^18? 1×10^-10 m 3×10^-10 m 3×10^26 m 9×10^26 m

the inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y. y = 3×10^8 / x what are the wavelengths for x - rays with frequency 3×10^18? 1×10^-10 m 3×10^-10 m 3×10^26 m 9×10^26 m

Answer

Answer:

A. $1\times 10^{-10}\text{ m}$

Explanation:

Step1: Substitute given values.

Given $y = 3\times 10^{18}$ and $y=\frac{3\times 10^{8}}{x}$, substitute $y$ into the equation: $3\times 10^{18}=\frac{3\times 10^{8}}{x}$.

Step2: Solve for $x$.

Cross - multiply to get $3\times 10^{18}x=3\times 10^{8}$. Then $x=\frac{3\times 10^{8}}{3\times 10^{18}}$.

Step3: Simplify the expression.

Using the rule $\frac{a^m}{a^n}=a^{m - n}$, we have $x = 1\times10^{8 - 18}=1\times 10^{-10}\text{ m}$.