joshua programs a robotic arm to place a block in a box by following the sequence of commands in the…

joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table\n| step | command |\n| ---- | ---- |\n| 1 | grip block |\n| 2 | lift block ten centimeters |\n| 3 | hold for twenty seconds |\n| 4 | release block |\nduring which step does the robotic arm do work on the block?\nstep 1\nstep 2\nstep 3\nstep 4
Answer
Explanation:
Step1: Recall work - definition
Work is done when a force causes a displacement in the direction of the force, $W = F\times d\times\cos\theta$ ($\theta$ is the angle between force and displacement).
Step2: Analyze Step 1
In Step 1, the robotic arm grips the block. There is no displacement of the block in the direction of the gripping force, so no work is done.
Step3: Analyze Step 2
In Step 2, the robotic arm exerts an upward force to lift the block a distance of ten centimeters. There is a displacement in the direction of the force, so work is done.
Step4: Analyze Step 3
In Step 3, the robotic arm holds the block for twenty seconds. There is no displacement of the block while the force is applied, so no work is done.
Step5: Analyze Step 4
In Step 4, the robotic arm releases the block. There is no force applied by the arm during the release process to cause a displacement, so no work is done.
Answer:
B. Step 2