julia produces a 2 ma current by moving the south pole of a bar magnet into a solenoid. the solenoid…

julia produces a 2 ma current by moving the south pole of a bar magnet into a solenoid. the solenoid contains 150 loops of wire. which change should julia make to generate a larger current? moving the magnet slower using more loops of wire in the coil using the north pole of the magnet setting the magnet down in the solenoid

julia produces a 2 ma current by moving the south pole of a bar magnet into a solenoid. the solenoid contains 150 loops of wire. which change should julia make to generate a larger current? moving the magnet slower using more loops of wire in the coil using the north pole of the magnet setting the magnet down in the solenoid

Answer

Brief Explanations:

According to Faraday's law of electromagnetic - induction, the induced emf ($\epsilon$) in a coil is given by $\epsilon=-N\frac{\Delta\Phi}{\Delta t}$, where $N$ is the number of turns in the coil and $\frac{\Delta\Phi}{\Delta t}$ is the rate of change of magnetic flux. Induced current $I = \frac{\epsilon}{R}$ (where $R$ is the resistance of the circuit). Increasing the number of loops $N$ will increase the induced emf and thus the induced current. Moving the magnet slower decreases the rate of change of magnetic flux, using the north - pole instead of the south - pole doesn't change the magnitude of the induced current, and setting the magnet down stops the change in magnetic flux and results in no induced current.

Answer:

using more loops of wire in the coil