julius competes in the hammer throw event. the hammer has a mass of 7.26 kg and is 1.215 m long. what is the…

julius competes in the hammer throw event. the hammer has a mass of 7.26 kg and is 1.215 m long. what is the centripetal force on the hammer when it has a tangential speed of 31.95 m/s? the answer is rounded off to the nearest whole number. 190 n 840 n 1,400 n 6,100 n

julius competes in the hammer throw event. the hammer has a mass of 7.26 kg and is 1.215 m long. what is the centripetal force on the hammer when it has a tangential speed of 31.95 m/s? the answer is rounded off to the nearest whole number. 190 n 840 n 1,400 n 6,100 n

Answer

Explanation:

Step1: Recall centripetal - force formula

The formula for centripetal force is $F_c=\frac{mv^{2}}{r}$, where $m$ is the mass, $v$ is the tangential speed, and $r$ is the radius.

Step2: Identify given values

We are given that $m = 7.26\ kg$, $v=31.95\ m/s$, and $r = 1.215\ m$.

Step3: Substitute values into formula

$F_c=\frac{7.26\times(31.95)^{2}}{1.215}$. First, calculate $(31.95)^{2}=31.95\times31.95 = 1020.8025$. Then, $7.26\times1020.8025 = 7401.02615$. Finally, $F_c=\frac{7401.02615}{1.215}\approx6107.84$.

Step4: Round to nearest whole number

Rounding $6107.84$ to the nearest whole - number gives $6108\approx6100\ N$.

Answer:

D. 6,100 N