kato traveled 5,000 meters north from her house with an average velocity of 4.5 m/s. what was the time of…

kato traveled 5,000 meters north from her house with an average velocity of 4.5 m/s. what was the time of her trip? (there are 60 seconds in 1 minute.)\n18.5 minutes\n20.4 minutes\n2 hours\n3 hours

kato traveled 5,000 meters north from her house with an average velocity of 4.5 m/s. what was the time of her trip? (there are 60 seconds in 1 minute.)\n18.5 minutes\n20.4 minutes\n2 hours\n3 hours

Answer

Explanation:

Step1: Recall velocity - time - distance formula

The formula is $v=\frac{d}{t}$, where $v$ is velocity, $d$ is distance and $t$ is time. We can re - arrange it to find time $t = \frac{d}{v}$.

Step2: Substitute given values

Given $d = 5000$ m and $v=4.5$ m/s. So $t=\frac{5000}{4.5}\text{ s}\approx1111.11\text{ s}$.

Step3: Convert seconds to minutes

Since there are 60 seconds in 1 minute, $t=\frac{1111.11}{60}\text{ minutes}\approx18.5$ minutes.

Answer:

18.5 minutes