a 2.0 kg cart moving in a straight line hits a piece of modeling clay (1.0 kg) that is at rest. the clay…

a 2.0 kg cart moving in a straight line hits a piece of modeling clay (1.0 kg) that is at rest. the clay sticks to the cart and both move to the left at 1.0 m/s. what was the initial velocity of the cart and in which direction? (remember to include - to indicate direction if necessary.)

a 2.0 kg cart moving in a straight line hits a piece of modeling clay (1.0 kg) that is at rest. the clay sticks to the cart and both move to the left at 1.0 m/s. what was the initial velocity of the cart and in which direction? (remember to include - to indicate direction if necessary.)

Answer

Explanation:

Step1: Aplicar la ley de conservación de la cantidad de movimiento

La cantidad de movimiento inicial (p_i) es igual a la cantidad de movimiento final (p_f). La fórmula es (m_1v_1 + m_2v_2=(m_1 + m_2)v_f). Aquí, (m_1 = 2.0\space kg), (m_2=1.0\space kg), (v_2 = 0\space m/s) (la arcilla está en reposo) y (v_f=- 1.0\space m/s) (dirección hacia la izquierda).

Step2: Sustituir los valores en la fórmula

Sustituimos los valores en la ecuación (2.0\times v_1+1.0\times0=(2.0 + 1.0)\times(-1.0)). Esto se simplifica a (2v_1=-3).

Step3: Resolver para (v_1)

Dividiendo ambos lados de la ecuación (2v_1=-3) por (2), obtenemos (v_1=\frac{-3}{2}=-1.5\space m/s).

Answer:

(v = - 1.5\space m/s)