if a 4.5 kg object is dropped from a height of 6.0 m, what will be its velocity when it is halfway toward…

if a 4.5 kg object is dropped from a height of 6.0 m, what will be its velocity when it is halfway toward the ground? (use g = 9.80 m/s², and ignore air resistance.)\no 7.7 m/s\no 11 m/s\no 16 m/s\no 29 m/s

if a 4.5 kg object is dropped from a height of 6.0 m, what will be its velocity when it is halfway toward the ground? (use g = 9.80 m/s², and ignore air resistance.)\no 7.7 m/s\no 11 m/s\no 16 m/s\no 29 m/s

Answer

Explanation:

Step1: Identify the relevant kinematic - equation

We use the equation $v^{2}=v_{0}^{2}+2a\Delta y$. The initial velocity $v_{0} = 0$ m/s (dropped object), the acceleration $a = g=9.80$ m/s², and the displacement $\Delta y$ is half of the initial height. The initial height $h = 6.0$ m, so $\Delta y=\frac{h}{2}=3.0$ m.

Step2: Substitute values into the equation

Since $v_{0} = 0$ m/s, the equation simplifies to $v^{2}=2g\Delta y$. Substituting $g = 9.80$ m/s² and $\Delta y = 3.0$ m, we get $v^{2}=2\times9.80\times3.0$. $v^{2}=58.8$.

Step3: Solve for $v$

Take the square - root of both sides: $v=\sqrt{58.8}\approx7.7$ m/s.

Answer:

7.7 m/s