what is the kinetic energy of a 478 kg object that is moving with a speed of 15 m/s?
what is the kinetic energy of a 478 kg object that is moving with a speed of 15 m/s?
Answer
Explanation:
Step1: Write the formula for kinetic energy
The formula for kinetic energy is ( KE=\frac{1}{2}mv^{2} ), where ( m ) is the mass of the object and ( v ) is the speed of the object.
Step2: Substitute the given values into the formula
Given ( m = 478\space kg ) and ( v=15\space m/s ). Substitute these values into the formula: ( KE=\frac{1}{2}\times478\times(15)^{2} ). First, calculate ( (15)^{2}=225 ). Then, ( \frac{1}{2}\times478 = 239 ).
Step3: Calculate the kinetic energy
Multiply ( 239\times225). ( 239\times225=(200 + 39)\times225=200\times225+39\times225=45000+8775 = 53775\space J )
Answer:
The kinetic energy of the object is ( 53775\space J )