what is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s? round to 3…

what is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s? round to 3 significant figures.\no 2,790 j\no 5,580 j\no 25,100 j\no 50,200 j
Answer
Explanation:
Step1: Recall kinetic - energy formula
The formula for kinetic energy is $K = \frac{1}{2}mv^{2}$, where $m$ is the mass and $v$ is the velocity.
Step2: Substitute given values
Given $m = 620.0\ kg$ and $v = 9.00\ m/s$. Substitute into the formula: $K=\frac{1}{2}\times620.0\times(9.00)^{2}$. First, calculate $(9.00)^{2}=81.00$. Then, $\frac{1}{2}\times620.0 = 310.0$. Next, $K=310.0\times81.00 = 25110\ J$.
Step3: Round to 3 significant figures
Rounding $25110\ J$ to 3 significant figures gives $25100\ J$.
Answer:
C. 25,100 J