knowns\n$v_i = 5\\text{ m/s}$\n$v_f = 15\\text{ m/s}$ at $t = 2\\text{ m/s}^2$\nunknown\n$10\\text{…

knowns\n$v_i = 5\\text{ m/s}$\n$v_f = 15\\text{ m/s}$ at $t = 2\\text{ m/s}^2$\nunknown\n$10\\text{ m/s}=?$\n2. solve for the unknown\nsolve for the change in velocity and the time taken to make that change.\nthe cahnge in velocity and the time taken to make that change is \nuse the definition of acceleration.\n3. evaluate the answer\n- are the units correct?\n- do the directions make sense?\nget it? describe the evidence that the planes at the beginning of this module are accelerating even if they are traveling at a constant speed.

knowns\n$v_i = 5\\text{ m/s}$\n$v_f = 15\\text{ m/s}$ at $t = 2\\text{ m/s}^2$\nunknown\n$10\\text{ m/s}=?$\n2. solve for the unknown\nsolve for the change in velocity and the time taken to make that change.\nthe cahnge in velocity and the time taken to make that change is \nuse the definition of acceleration.\n3. evaluate the answer\n- are the units correct?\n- do the directions make sense?\nget it? describe the evidence that the planes at the beginning of this module are accelerating even if they are traveling at a constant speed.

Answer

Explanation:

Step1: Encontrar el cambio en velocidad

El cambio en velocidad $\Delta v$ se calcula como $v_f - v_i$. Dado que $v_i = 5\ m/s$ y $v_f=15\ m/s$, entonces $\Delta v=v_f - v_i=15 - 5=10\ m/s$.

Step2: Encontrar el tiempo

Sabemos que la aceleración $a = 2\ m/s^2$ y que $a=\frac{\Delta v}{\Delta t}$. Re - arreglando la fórmula para $\Delta t$, tenemos $\Delta t=\frac{\Delta v}{a}$. Sustituyendo $\Delta v = 10\ m/s$ y $a = 2\ m/s^2$, obtenemos $\Delta t=\frac{10}{2}=5\ s$.

Answer:

El cambio en velocidad es $10\ m/s$ y el tiempo tomado para hacer ese cambio es $5\ s$.