koto traveled 5,000 meters north from her house with an average velocity of 4.5 m/s. what was the time of…

koto traveled 5,000 meters north from her house with an average velocity of 4.5 m/s. what was the time of her trip? (there are 60 seconds in 1 minute.)\no 18.5 minutes\no 20.4 minutes\no 2 hours\no 3 hours

koto traveled 5,000 meters north from her house with an average velocity of 4.5 m/s. what was the time of her trip? (there are 60 seconds in 1 minute.)\no 18.5 minutes\no 20.4 minutes\no 2 hours\no 3 hours

Answer

Explanation:

Step1: Recall velocity - time formula

We know that velocity $v=\frac{d}{t}$, where $d$ is distance and $t$ is time. Rearranging for time gives $t = \frac{d}{v}$.

Step2: Substitute given values

Given $d = 5000$ m and $v=4.5$ m/s. So $t=\frac{5000}{4.5}\text{ s}\approx1111.11\text{ s}$.

Step3: Convert seconds to minutes

Since there are 60 seconds in 1 minute, $t=\frac{1111.11}{60}\text{ minutes}\approx 18.5$ minutes.

Answer:

18.5 minutes