a light bulb has a resistance of 360 ω. what is the current in the bulb when it has a potential difference…

a light bulb has a resistance of 360 ω. what is the current in the bulb when it has a potential difference of 120 v across it?\n0.33 a\n3 a\n480 a\n43,200 a

a light bulb has a resistance of 360 ω. what is the current in the bulb when it has a potential difference of 120 v across it?\n0.33 a\n3 a\n480 a\n43,200 a

Answer

Explanation:

Step1: Identificar la ley de Ohm

La ley de Ohm es $V = IR$, donde $V$ es la diferencia de potencial, $I$ es la corriente y $R$ es la resistencia. Queremos encontrar $I$, entonces despejamos $I=\frac{V}{R}$.

Step2: Sustituir valores

Dado que $V = 120\ V$ y $R=360\ \Omega$, entonces $I=\frac{120}{360}=\frac{1}{3}\approx0.33\ A$.

Answer:

A. 0.33 A