light of a certain energy shines on a metal and causes electrons to be emitted. based on the research of…

light of a certain energy shines on a metal and causes electrons to be emitted. based on the research of albert einstein, what change would most likely result in stopping the emission of electrons from this metal? an increase in the intensity of the light a decrease in the intensity of the light the use of light that has a higher frequency the use of light that has a lower frequency

light of a certain energy shines on a metal and causes electrons to be emitted. based on the research of albert einstein, what change would most likely result in stopping the emission of electrons from this metal? an increase in the intensity of the light a decrease in the intensity of the light the use of light that has a higher frequency the use of light that has a lower frequency

Answer

Brief Explanations:

According to Einstein's photoelectric - effect theory, electrons are emitted when photons with sufficient energy (related to frequency) strike a metal. The energy of a photon is given by $E = h\nu$ (where $h$ is Planck's constant and $\nu$ is frequency). If the frequency of the incident light is below the threshold frequency of the metal, no electrons will be emitted regardless of the light intensity. Increasing or decreasing intensity only changes the number of photons, not their individual energy. Using light with a higher frequency increases photon energy, while using light with a lower frequency may reduce it below the threshold.

Answer:

D. the use of light that has a lower frequency