light travels at a rate of 3.0×10^8 meters per second. if the earth is 1.5×10^11 meters away from the sun…

light travels at a rate of 3.0×10^8 meters per second. if the earth is 1.5×10^11 meters away from the sun, how long does it take for light to travel from the sun to the earth?\na 2.0×10^3 seconds\nb 4.5×10^19 seconds\nc 4.5×10^88 seconds\nd 5.0×10^2 seconds\ne 5.0×10^3 seconds

light travels at a rate of 3.0×10^8 meters per second. if the earth is 1.5×10^11 meters away from the sun, how long does it take for light to travel from the sun to the earth?\na 2.0×10^3 seconds\nb 4.5×10^19 seconds\nc 4.5×10^88 seconds\nd 5.0×10^2 seconds\ne 5.0×10^3 seconds

Answer

Explanation:

Step1: Recall the time - distance - speed formula

We know that $t=\frac{d}{v}$, where $t$ is time, $d$ is distance and $v$ is speed.

Step2: Substitute the given values

Given $d = 1.5\times10^{11}$ meters and $v=3.0\times 10^{8}$ meters per second. Then $t=\frac{1.5\times 10^{11}}{3.0\times 10^{8}}$.

Step3: Simplify the expression

Using the rule of exponents $\frac{a\times10^{m}}{b\times10^{n}}=\frac{a}{b}\times10^{m - n}$, we have $\frac{1.5}{3.0}\times10^{11-8}=0.5\times10^{3}$.

Step4: Convert to scientific notation

$0.5\times10^{3}=5.0\times10^{2}$ seconds.

Answer:

D. $5.0\times 10^{2}$ seconds