a log is either oak or pine. it displaces 2.7 gal of water and weighs 13.8 lb.\npart a\ncalculate the…

a log is either oak or pine. it displaces 2.7 gal of water and weighs 13.8 lb.\npart a\ncalculate the density of the log in g/cm³.\nexpress your answer using two significant figures.\n0.88 g/cm³\nprevious answers\nall attempts used; correct answer withheld by instructor\nthe correct answer does not depend on: cm.\npart b\nis the log oak or pine? (density of oak = 0.9 g/cm³; density of pine = 0.4 g/cm³)\nthe log is oak because the calculated density aligns with the density of oak\nthe log is pine because the calculated density aligns with the density of pine\nthe log is neither density nor pine because the calculated density does not align with the density of either type

a log is either oak or pine. it displaces 2.7 gal of water and weighs 13.8 lb.\npart a\ncalculate the density of the log in g/cm³.\nexpress your answer using two significant figures.\n0.88 g/cm³\nprevious answers\nall attempts used; correct answer withheld by instructor\nthe correct answer does not depend on: cm.\npart b\nis the log oak or pine? (density of oak = 0.9 g/cm³; density of pine = 0.4 g/cm³)\nthe log is oak because the calculated density aligns with the density of oak\nthe log is pine because the calculated density aligns with the density of pine\nthe log is neither density nor pine because the calculated density does not align with the density of either type

Answer

Explanation:

Step1: Convert volume units

1 gal = 3785.41 cm³, so 2.7 gal = 2.7×3785.41 = 10220.607 cm³.

Step2: Convert mass units

1 lb = 453.592 g, so 13.8 lb = 13.8×453.592 = 6259.57 g.

Step3: Calculate density

Density $\rho=\frac{m}{V}$, where $m$ is mass and $V$ is volume. $\rho=\frac{6259.57}{10220.607}\approx0.61$ g/cm³ (rounded to two - significant figures).

For Part B: Since the density of oak is 0.9 g/cm³ and the density of pine is 0.4 g/cm³, and the calculated density of the log is approximately 0.61 g/cm³, the log is neither oak nor pine because the calculated density does not align with the density of either type.

Answer:

Part A: $0.61$ g/cm³ Part B: The log is neither oak nor pine because the calculated density does not align with the density of either type.