looking into the sky one night, tori wondered how far into outer space she would get if she drove a car for…

looking into the sky one night, tori wondered how far into outer space she would get if she drove a car for 3.21 × 10³ hours at a rate of 70mph. she calculated and determined that a car travelling at 70 mph covers approximately 1.13 × 10⁵ meters per hour. tori wrote this expression to determine the distance she would travel into outer space. (3.21 × 10³)(1.13 × 10⁵) estimate the distance travelled. ≈30 × 10¹⁵ meters ≈3 × 10⁸ meters ≈30 × 10⁸ meters ≈3 × 10¹⁵ meters

looking into the sky one night, tori wondered how far into outer space she would get if she drove a car for 3.21 × 10³ hours at a rate of 70mph. she calculated and determined that a car travelling at 70 mph covers approximately 1.13 × 10⁵ meters per hour. tori wrote this expression to determine the distance she would travel into outer space. (3.21 × 10³)(1.13 × 10⁵) estimate the distance travelled. ≈30 × 10¹⁵ meters ≈3 × 10⁸ meters ≈30 × 10⁸ meters ≈3 × 10¹⁵ meters

Answer

Answer:

$\approx3\times 10^{8}$ meters

Explanation:

Step1: Multiply the coefficients

$3.21\times1.13 = 3.6273\approx4$

Step2: Add the exponents of 10

$10^{3}\times10^{5}=10^{3 + 5}=10^{8}$

Step3: Combine the results

$4\times10^{8}\approx3\times 10^{8}$ (round - off for approximation)