a loop of area 0.0303 m2 is oriented perpendicular (0 deg) to a magnetic field. the magnetic flux through…

a loop of area 0.0303 m2 is oriented perpendicular (0 deg) to a magnetic field. the magnetic flux through the loop is 0.0261 wb. what is the value of the magnetic field? ? t

a loop of area 0.0303 m2 is oriented perpendicular (0 deg) to a magnetic field. the magnetic flux through the loop is 0.0261 wb. what is the value of the magnetic field? ? t

Answer

Explanation:

Step1: Recall magnetic - flux formula

The formula for magnetic flux is $\varPhi = B\cdot A\cdot\cos\theta$, where $\varPhi$ is the magnetic flux, $B$ is the magnetic - field strength, $A$ is the area of the loop, and $\theta$ is the angle between the normal to the loop and the magnetic field. Since the loop is perpendicular to the magnetic field, $\theta = 0^{\circ}$ and $\cos\theta=\cos(0^{\circ}) = 1$. So the formula simplifies to $\varPhi=B\cdot A$.

Step2: Solve for magnetic - field strength

We need to find $B$. Rearranging the formula $\varPhi = B\cdot A$ for $B$, we get $B=\frac{\varPhi}{A}$. Given that $\varPhi = 0.0261\ \text{Wb}$ and $A = 0.0303\ \text{m}^2$, we substitute these values into the formula: $B=\frac{0.0261}{0.0303}$. $B\approx0.861\ \text{T}$

Answer:

$0.861$