what is the magnitude and direction of the force in the free body diagram shown?
what is the magnitude and direction of the force in the free body diagram shown?
Answer
Explanation:
Step1: Determine the net force
We know that forces are vectors. Let's assume the right - hand direction is positive and the left - hand direction is negative. The force on the left is (F_1=- 160N) (negative because it's to the left) and the force on the right is (F_2 = 90N) (positive because it's to the right). The net force (F_{net}=F_1 + F_2) [F_{net}=-160 + 90]
Step2: Calculate the value of the net force
[F_{net}=-70N] The negative sign indicates the direction of the net force.
Answer:
(70N) to the left.