magnitude of an earthquake : $m = \\log \\frac{i}{s}$\nwhat is the magnitude of an earthquake that is 10,000…

magnitude of an earthquake : $m = \\log \\frac{i}{s}$\nwhat is the magnitude of an earthquake that is 10,000 times more intense than a standard earthquake?\n$m = $\ndone

magnitude of an earthquake : $m = \\log \\frac{i}{s}$\nwhat is the magnitude of an earthquake that is 10,000 times more intense than a standard earthquake?\n$m = $\ndone

Answer

Explanation:

Step1: Define the intensity ratio

Given that the earthquake is 10000 times more intense than a standard earthquake, so $\frac{I}{S}=10000$.

Step2: Calculate the magnitude

Substitute $\frac{I}{S}=10000$ into the magnitude - formula $M = \log\frac{I}{S}$. Since $\log_{10}10000=\log_{10}10^{4}$, and by the property of logarithms $\log_{a}a^{b}=b$, we have $M = 4$.

Answer:

4