2. how many °f are there between the temperature at which water freezes (0 °c) and the temperature at which…
2. how many °f are there between the temperature at which water freezes (0 °c) and the temperature at which water boils (100 °c)?
Answer
Explanation:
Step1: Recall the Celsius - Fahrenheit conversion formula
The formula to convert Celsius ($C$) to Fahrenheit ($F$) is $F=\frac{9}{5}C + 32$.
Step2: Convert 0°C to Fahrenheit
Substitute $C = 0$ into the formula: $F_1=\frac{9}{5}\times0+32=32^{\circ}F$.
Step3: Convert 100°C to Fahrenheit
Substitute $C = 100$ into the formula: $F_2=\frac{9}{5}\times100 + 32=9\times20+32=180 + 32=212^{\circ}F$.
Step4: Calculate the difference
Find the difference $\Delta F=F_2 - F_1=212 - 32=180^{\circ}F$.
Answer:
$180^{\circ}F$