mark creates a graphic organizer to review his notes about electrical force. which labels belong in the…

Explanation:

Step1: Recall Coulomb's law

The electrical force (F = k\frac{q_1q_2}{r^2}), where (k) is a constant, (q_1) and (q_2) are charges, and (r) is the distance between the charges.

Step2: Analyze the effect of distance ((X))

If we consider the effect of distance (r) on the force, when (r) is decreased to half ((r'=\frac{r}{2})), then (F'=k\frac{q_1q_2}{(\frac{r}{2})^2}=k\frac{q_1q_2}{\frac{r^2}{4}} = 4k\frac{q_1q_2}{r^2}=4F). So decreasing the distance to half quadruples the force.

Step3: Analyze the effect of charge ((Y))

If we consider the effect of one - of the charges, say (q_1), if we double (q_1) (i.e., (q_1' = 2q_1)), then (F'=k\frac{(2q_1)q_2}{r^2}=2k\frac{q_1q_2}{r^2}=2F). So doubling a charge doubles the force.

Answer:

X: Decreasing to half will quadruple force Y: Doubling will double force