mary throws a plastic disc to her friend. her friend catches the disc six seconds after mary throws it. the…

mary throws a plastic disc to her friend. her friend catches the disc six seconds after mary throws it. the table shows the height of the disc at one - second intervals. assuming that the throw represents projectile motion, what are the missing values in the table? time (seconds) height (feet) 0 3 1 a 2 6 3 7 4 6 5 4 6 b a = 5, b = 3 a = 4, b = 0 a = 4, b = 3 a = 5, b = 0

mary throws a plastic disc to her friend. her friend catches the disc six seconds after mary throws it. the table shows the height of the disc at one - second intervals. assuming that the throw represents projectile motion, what are the missing values in the table? time (seconds) height (feet) 0 3 1 a 2 6 3 7 4 6 5 4 6 b a = 5, b = 3 a = 4, b = 0 a = 4, b = 3 a = 5, b = 0

Answer

Answer:

D. $A = 5, B = 0$

Explanation:

Step1: Analyze projectile - motion symmetry

Projectile motion is symmetric about the vertex. The vertex occurs at $t = 3$ with height $h = 7$.

Step2: Find value of $A$

At $t = 1$ and $t = 5$, the heights are symmetric about $t = 3$. Since at $t = 5$, $h = 4$, at $t = 1$, $A=4 + 1=5$.

Step3: Find value of $B$

The disc is caught at $t = 6$. Since the motion started at $h = 3$ and considering the nature of projectile - motion coming back to the same horizontal level (caught at the same height as the initial height relative to the thrower - catcher horizontal plane), at $t = 6$, $B = 0$.