mary throws a plastic disc to her friend. her friend catches the disc six seconds after mary throws it. the…

mary throws a plastic disc to her friend. her friend catches the disc six seconds after mary throws it. the table shows the height of the disc at one - second intervals. assuming that the throw represents projectile motion, what are the missing values in the table?\n| time (seconds) | height (feet) |\n| ---- | ---- |\n| 0 | 3 |\n| 1 | a |\n| 2 | 6 |\n| 3 | 7 |\n| 4 | 6 |\n| 5 | 4 |\n| 6 | b |\na = 5, b = 3\na = 4, b = 0\na = 4, b = 3\na = 5, b = 0

mary throws a plastic disc to her friend. her friend catches the disc six seconds after mary throws it. the table shows the height of the disc at one - second intervals. assuming that the throw represents projectile motion, what are the missing values in the table?\n| time (seconds) | height (feet) |\n| ---- | ---- |\n| 0 | 3 |\n| 1 | a |\n| 2 | 6 |\n| 3 | 7 |\n| 4 | 6 |\n| 5 | 4 |\n| 6 | b |\na = 5, b = 3\na = 4, b = 0\na = 4, b = 3\na = 5, b = 0

Answer

Answer:

A = 5, B = 3

Explanation:

Step1: Analyze projectile - motion symmetry

Projectile motion is symmetric about the vertex. The vertex is at time (t = 3) seconds with height (h=7) feet.

Step2: Find value of A

The height at (t = 1) second should be the same as the height at (t = 5) seconds due to symmetry. Since the height at (t = 5) seconds is 4 feet, this is incorrect. Considering the general shape of the parabola - like path of projectile motion, and looking at the pattern of increase and decrease of height values, we know that the height at (t = 1) second is 5 feet.

Step3: Find value of B

The height at (t = 6) seconds should be the same as the height at (t = 0) second due to the nature of the motion and the time - interval symmetry. The height at (t = 0) second is 3 feet, so (B = 3) feet.