masako measures a circuit at 12 v and 2 a. using ohms law, what can he calculate for the circuit?\nresistance…

masako measures a circuit at 12 v and 2 a. using ohms law, what can he calculate for the circuit?\nresistance (ω)\nresistance (o)\ncurrent (i)\ncurrent (ω)

masako measures a circuit at 12 v and 2 a. using ohms law, what can he calculate for the circuit?\nresistance (ω)\nresistance (o)\ncurrent (i)\ncurrent (ω)

Answer

Explanation:

Step1: Recall Ohm's law formula

Ohm's law is (V = IR), where (V) is voltage, (I) is current, and (R) is resistance.

Step2: Rearrange the formula to solve for resistance

We can rewrite (V = IR) as (R=\frac{V}{I}).

Step3: Substitute the given values

Given (V = 12\space V) and (I = 2\space A), then (R=\frac{12}{2}=6\space\Omega). Also, the unit of resistance is ohm ((\Omega)), current is ampere ((A)).

Answer:

resistance ((\Omega))