what is the mass of a 3.00 cm3 piece of gold having a density of 19.3 g/cm3? mass = ? g record your answer…

Explanation:

Step1: Recall density - mass - volume formula

The formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass and $V$ is volume. We can re - arrange it to solve for mass: $m = \rho\times V$.

Step2: Substitute given values

Given $\rho = 19.3\ g/cm^{3}$ and $V=3.00\ cm^{3}$. Then $m=19.3\ g/cm^{3}\times3.00\ cm^{3}$.

Step3: Calculate the mass

$m = 19.3\times3.00=57.9\ g$.

Answer:

$57.9$