mission kc3: speed and velocity\na football coach starts at the 35 - yard line (a) and walks to the 15…

mission kc3: speed and velocity\na football coach starts at the 35 - yard line (a) and walks to the 15 - yard line (b). he turns around and walks to the 40 - yard line (c). he turns around again and walks back to the 0 - yard line (d). he turns around once more and walks back to the 25 - yard line (e), thus completing his 10 minutes of pacing. the coachs average speed is \n a. 0.5 y/min, east\n b. 0.5 y/min, west\n c. 0.5 y/min\n d. 1.0 y/min, east\n e. 1.0 y/min, west\n f. 1.0 y/min\n g. 3.5 y/min, east\n h. 3.5 y/min, west\n i. 3.5 y/min\n j. 4.0 y/min, east\n k. 4.0 y/min, west\n l. 4.0 y/min\n m. 11.0 y/min, east\n n. 11.0 y/min, west\n o. 11.0 y/min\n p. none of these
Answer
Explanation:
Step1: Calculate total distance
Distance from A(35) to B(15) is $|35 - 15|=20$ yards. Distance from B(15) to C(40) is $|40 - 15| = 25$ yards. Distance from C(40) to D(0) is $|40-0|=40$ yards. Distance from D(0) to E(25) is $|25 - 0|=25$ yards. Total distance $d=20 + 25+40 + 25=110$ yards.
Step2: Calculate average speed
Average speed formula is $v=\frac{d}{t}$. Given $t = 10$ minutes. $v=\frac{110}{10}=11.0$ y/min. Speed is a scalar quantity, has no direction.
Answer:
o. 11.0 y/min