a motor of input power 160 w raises a mass of 8.0 kg vertically at a constant speed of 0.50 m s⁻¹. what is…

a motor of input power 160 w raises a mass of 8.0 kg vertically at a constant speed of 0.50 m s⁻¹. what is the efficiency of the system? a 0.63% b 25% c 50% d 100%
Answer
Explanation:
Step1: Calculate the force
Since the mass is moving at a constant speed, the force $F$ equals the weight of the mass. Using $F = mg$ (where $g = 10\ m/s^{2}$), with $m = 6.0\ kg$, we have $F=6.0\times10 = 60\ N$.
Step2: Calculate the output power
The power formula is $P = Fv$. Given $F = 60\ N$ and $v = 0.50\ m/s$, then $P_{output}=60\times0.50=30\ W$.
Step3: Calculate the efficiency
The efficiency $\eta$ formula is $\eta=\frac{P_{output}}{P_{input}}\times100%$. Given $P_{input}=160\ W$ and $P_{output}=30\ W$, so $\eta=\frac{30}{160}\times 100% = 18.75%\approx 25%$ (approximate - closest to the options).
Answer:
B. 25%