mrs. mccloud is conducting an experiment with her science class. she ties a weather balloon to a tether…

mrs. mccloud is conducting an experiment with her science class. she ties a weather balloon to a tether until she is ready to release it. once mrs. mccloud releases the balloon, it slowly rises. this situation can be modeled as a linear relationship. complete the statement that describes the situation. the weather balloon is feet above the ground while tethered. after mrs. mccloud releases the balloon, it rises

mrs. mccloud is conducting an experiment with her science class. she ties a weather balloon to a tether until she is ready to release it. once mrs. mccloud releases the balloon, it slowly rises. this situation can be modeled as a linear relationship. complete the statement that describes the situation. the weather balloon is feet above the ground while tethered. after mrs. mccloud releases the balloon, it rises

Answer

Explanation:

Step1: Find initial height

The y - intercept of the linear graph represents the height of the balloon when it is tethered. When (x = 0) (time of release is 0 minutes), from the graph, (y=100). So the balloon is 100 feet above the ground while tethered.

Step2: Calculate rate of rise

The slope of the line gives the rate at which the balloon rises. We can use two points ((x_1,y_1)=(0,100)) and ((x_2,y_2)=(10,450)). The slope (m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{450 - 100}{10-0}=\frac{350}{10}=35). So the balloon rises 35 feet per minute.

Answer:

The weather balloon is 100 feet above the ground while tethered. After Mrs. McCloud releases the balloon, it rises 35 feet per minute.