4. how much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from…

4. how much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°c to 65°c? note: water has a specific heat of 4,190 j/kg °c.

4. how much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°c to 65°c? note: water has a specific heat of 4,190 j/kg °c.

Answer

Explanation:

Step1: Identify the formula

The formula for heat energy is $Q = mc\Delta T$, where $Q$ is the heat energy, $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature.

Step2: Calculate the change in temperature

$\Delta T=T_2 - T_1=65^{\circ}C - 30^{\circ}C = 35^{\circ}C$

Step3: Substitute the values into the formula

$m = 0.5\ kg$, $c = 4190\ J/kg^{\circ}C$, $\Delta T=35^{\circ}C$. Then $Q=mc\Delta T=(0.5\ kg)\times(4190\ J/kg^{\circ}C)\times35^{\circ}C$ $Q = 0.5\times4190\times35\ J=73325\ J$

Answer:

$73325\ J$