how much heat, in joules, is required to heat a 28.4 - g (1 - oz) ice cube from - 23.0 °c to - 1.0 °c? (the…

how much heat, in joules, is required to heat a 28.4 - g (1 - oz) ice cube from - 23.0 °c to - 1.0 °c? (the specific heat capacity of ice is 2.093 j/g·°c.) (if you wish, you can show math work for possible partial credit.)

how much heat, in joules, is required to heat a 28.4 - g (1 - oz) ice cube from - 23.0 °c to - 1.0 °c? (the specific heat capacity of ice is 2.093 j/g·°c.) (if you wish, you can show math work for possible partial credit.)

Answer

Explanation:

Step1: Identify the formula

The formula for heat $Q = mc\Delta T$, where $m$ is mass, $c$ is specific - heat capacity, and $\Delta T$ is the change in temperature.

Step2: Calculate the change in temperature

$\Delta T=T_{f}-T_{i}=- 1.0^{\circ}C-(-23.0^{\circ}C)=22.0^{\circ}C$

Step3: Substitute values into the formula

$m = 28.4\ g$, $c = 2.093\ J/g\cdot^{\circ}C$, $\Delta T=22.0^{\circ}C$ $Q=mc\Delta T=(28.4\ g)\times(2.093\ J/g\cdot^{\circ}C)\times(22.0^{\circ}C)$ $Q = 28.4\times2.093\times22.0\ J$ $Q=28.4\times46.046\ J$ $Q = 1307.7064\ J\approx1308\ J$

Answer:

$1308\ J$