2. how much heat is needed to raise the temperature of a 2 kg sample of liquid water from 300 k to 355 k?
2. how much heat is needed to raise the temperature of a 2 kg sample of liquid water from 300 k to 355 k?
Answer
Explanation:
Step1: Identify the formula
The formula for heat $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature. The specific - heat capacity of liquid water $c = 4186\ J/(kg\cdot K)$.
Step2: Calculate the change in temperature
$\Delta T=T_2 - T_1=355\ K - 300\ K = 55\ K$.
Step3: Calculate the heat
$Q=mc\Delta T$. Substitute $m = 2\ kg$, $c = 4186\ J/(kg\cdot K)$, and $\Delta T = 55\ K$ into the formula. $Q=2\ kg\times4186\ J/(kg\cdot K)\times55\ K$. $Q = 2\times4186\times55\ J$. $Q=460460\ J$.
Answer:
$460460\ J$