how much heat is released when 25.0 grams of liquid copper at its freezing point of 1,085°c changes to…

how much heat is released when 25.0 grams of liquid copper at its freezing point of 1,085°c changes to solid? the latent heat of fusion of copper is 205.0 j/g.\n-27,130 j\n-5,130 j\n5,130 j\n27,130 j

how much heat is released when 25.0 grams of liquid copper at its freezing point of 1,085°c changes to solid? the latent heat of fusion of copper is 205.0 j/g.\n-27,130 j\n-5,130 j\n5,130 j\n27,130 j

Answer

Explanation:

Step1: Identify the formula

The formula for heat released during a phase - change at constant temperature is $Q = m\times L_f$, where $m$ is the mass and $L_f$ is the latent heat of fusion.

Step2: Substitute the values

Given $m = 25.0\ g$ and $L_f=205.0\ J/g$. Then $Q=25.0\ g\times205.0\ J/g$.

Step3: Calculate the result

$Q = 5125\ J\approx5130\ J$. Since heat is released during freezing, the sign of $Q$ is negative. So $Q=- 5130\ J$.

Answer:

-5,130 J