how much heat is required to heat 50.0 g of gold from 25.0 to 29.0 °c if the specific heat is 0.0305…

how much heat is required to heat 50.0 g of gold from 25.0 to 29.0 °c if the specific heat is 0.0305 cal/g°c?\nwhat unit are you solving for?\ng\n°c\ncal\nnone, i hate units
Answer
Explanation:
Step1: Identify the formula
The formula for heat is $q = mc\Delta T$, where $q$ is heat, $m$ is mass, $c$ is specific - heat, and $\Delta T$ is change in temperature. We are solving for $q$, and the unit of $q$ in the given specific - heat unit context is cal.
Step2: Calculate the change in temperature
$\Delta T=T_2 - T_1=29.0^{\circ}C - 25.0^{\circ}C = 4.0^{\circ}C$
Step3: Substitute values into the formula
$m = 50.0\ g$, $c=0.0305\ cal/g^{\circ}C$, $\Delta T = 4.0^{\circ}C$ $q=mc\Delta T=(50.0\ g)\times(0.0305\ cal/g^{\circ}C)\times(4.0^{\circ}C)$ $q = 6.1\ cal$
Answer:
cal