how much of a radioactive kind of francium will be left after 44 minutes if you start with 2,616 grams and…

Explanation:

Step1: Calculate number of half - lives

The formula to find the number of half - lives $n=\frac{t}{T_{1/2}}$, where $t$ is the time elapsed and $T_{1/2}$ is the half - life. Given $t = 44$ minutes and $T_{1/2}=22$ minutes. So, $n=\frac{44}{22}=2$.

Step2: Use the radioactive decay formula

The formula for radioactive decay is $N = N_0\times(\frac{1}{2})^n$, where $N_0$ is the initial amount, $n$ is the number of half - lives, and $N$ is the final amount. Here, $N_0 = 2616$ grams and $n = 2$. Then $N=2616\times(\frac{1}{2})^2$. $N = 2616\times\frac{1}{4}=654$.

Answer:

654