how much of a radioactive kind of neodymium will be left after 33 days if the half - life is 11 days and you…
how much of a radioactive kind of neodymium will be left after 33 days if the half - life is 11 days and you start with 80 grams? grams
Answer
Explanation:
Step1: Calculate the number of half - lives
The number of half - lives $n=\frac{t}{T}$, where $t = 33$ days is the time elapsed and $T = 11$ days is the half - life. So $n=\frac{33}{11}=3$.
Step2: Use the radioactive decay formula
The formula for radioactive decay is $N = N_0\times(\frac{1}{2})^n$, where $N_0 = 80$ grams is the initial amount and $n$ is the number of half - lives. Substitute $N_0 = 80$ and $n = 3$ into the formula: $N=80\times(\frac{1}{2})^3$.
Step3: Calculate the remaining amount
$(\frac{1}{2})^3=\frac{1}{8}$, and $N = 80\times\frac{1}{8}=10$.
Answer:
10