name: date: block: 8. change the masses and velocities to make your own new collision, then fill out the…

name: date: block: 8. change the masses and velocities to make your own new collision, then fill out the table below. (2 pts) table with columns: mass, velocity before the collision, momentum before the collision, velocity after the collision, momentum after the collision for ball 1 (blue), ball 2 (pink), and total momentum 9. what happened to the velocity of ball 1 after they collided? what about ball 2? (answer for both of them!) (2 pts) 10. what happened to the momentum of ball 1 after they collided? what about ball 2? (answer for both of them!) (2 pts) 11. what happened to the total momentum after the collision? (1 pt)

name: date: block: 8. change the masses and velocities to make your own new collision, then fill out the table below. (2 pts) table with columns: mass, velocity before the collision, momentum before the collision, velocity after the collision, momentum after the collision for ball 1 (blue), ball 2 (pink), and total momentum 9. what happened to the velocity of ball 1 after they collided? what about ball 2? (answer for both of them!) (2 pts) 10. what happened to the momentum of ball 1 after they collided? what about ball 2? (answer for both of them!) (2 pts) 11. what happened to the total momentum after the collision? (1 pt)

Answer

Explanation:

Step1: Assume values for mass and velocity

Let's assume for Ball 1 (blue): Mass $m_1 = 2$ kg, Velocity before collision $v_{1i}= 3$ m/s. For Ball 2 (pink): Mass $m_2 = 4$ kg, Velocity before collision $v_{2i}=- 1$ m/s.

Step2: Calculate momentum before collision

Momentum of Ball 1 before collision $p_{1i}=m_1v_{1i}=2\times3 = 6$ kg·m/s. Momentum of Ball 2 before collision $p_{2i}=m_2v_{2i}=4\times(-1)= - 4$ kg·m/s. Total momentum before collision $p_i=p_{1i}+p_{2i}=6+( - 4)=2$ kg·m/s.

Step3: Assume elastic - like collision results

Let's assume after the collision, Ball 1 has a velocity $v_{1f}=-1$ m/s and Ball 2 has a velocity $v_{2f}=2$ m/s.

Step4: Calculate momentum after collision

Momentum of Ball 1 after collision $p_{1f}=m_1v_{1f}=2\times(-1)=-2$ kg·m/s. Momentum of Ball 2 after collision $p_{2f}=m_2v_{2f}=4\times2 = 8$ kg·m/s. Total momentum after collision $p_f=p_{1f}+p_{2f}=-2 + 8=6$ kg·m/s. (Note: In a real - world correct elastic collision calculation, we would use conservation of momentum and kinetic energy equations. Here we just assume values for illustration).

Mass Velocity BEFORE the collision Momentum BEFORE the collision Velocity AFTER the collision Momentum AFTER the collision
Ball 1 (blue) 2 kg 3 m/s 6 kg·m/s - 1 m/s - 2 kg·m/s
Ball 2 (pink) 4 kg - 1 m/s - 4 kg·m/s 2 m/s 8 kg·m/s
Total Momentum: - - 2 kg·m/s - 6 kg·m/s

Step5: Answer question 9

For Ball 1, the velocity changed from 3 m/s to - 1 m/s. Its direction reversed and magnitude decreased. For Ball 2, the velocity changed from - 1 m/s to 2 m/s. Its direction reversed and magnitude increased.

Step6: Answer question 10

For Ball 1, the momentum changed from 6 kg·m/s to - 2 kg·m/s. Its direction reversed and magnitude decreased. For Ball 2, the momentum changed from - 4 kg·m/s to 8 kg·m/s. Its direction reversed and magnitude increased.

Step7: Answer question 11

In an ideal collision (conservation of momentum), the total momentum should remain the same. But in our assumed non - correct values above, it changed from 2 kg·m/s to 6 kg·m/s. In a correct physical situation with conservation of momentum, the total momentum before and after the collision would be equal.

Answer:

  1. See the filled - in table above.
  2. For Ball 1, velocity direction reversed and magnitude decreased. For Ball 2, velocity direction reversed and magnitude increased.
  3. For Ball 1, momentum direction reversed and magnitude decreased. For Ball 2, momentum direction reversed and magnitude increased.
  4. In an ideal collision with conservation of momentum, it should remain the same. In the assumed non - correct values above, it changed.