what is the net displacement of the particle between 0 seconds and 80 seconds?\na. 160 meters\nb. 80…

Explanation:

Step1: Recall displacement - velocity relation

Displacement is the area under the velocity - time graph.

Step2: Divide the graph into shapes

The graph can be divided into two triangles from 0 - 40 s and 40 - 80 s.

Step3: Calculate area of first triangle (0 - 40 s)

The base of the first triangle from 0 - 40 s is $b_1 = 40$ s and height $h_1=4$ m/s. The area of a triangle is $A=\frac{1}{2}bh$. So $A_1=\frac{1}{2}\times40\times4 = 80$ m.

Step4: Calculate area of second triangle (40 - 80 s)

The base of the second triangle from 40 - 80 s is $b_2 = 40$ s and height $h_2=- 4$ m/s. The area $A_2=\frac{1}{2}\times40\times(-4)=- 80$ m.

Step5: Calculate net displacement

Net displacement $d = A_1+A_2=80+( - 80)=0$ m.

Answer:

E. 0 meters