what is the new volume when an expandable 4.51 l container of gas at 273 k is warmed to 546 k?\nv =…

Explanation:

Step1: Identify the gas - law formula

Since the number of moles and pressure are constant, we use Charles's law: $\frac{V_1}{T_1}=\frac{V_2}{T_2}$.

Step2: Assign values

$V_1 = 4.51\ L$, $T_1=273\ K$, $T_2 = 546\ K$, and $V_2$ is the unknown.

Step3: Rearrange the formula to solve for $V_2$

$V_2=\frac{V_1T_2}{T_1}$.

Step4: Substitute values and calculate

$V_2=\frac{4.51\ L\times546\ K}{273\ K}=9.02\ L$.

Answer:

$9.02$