1. a nitrogen gas sample is measured at 7.00l and 119kpa at a temperature of 330k. if the pressure and…

Explanation:

Step1: Recall the combined - gas law

The combined - gas law is $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$, where $P_1$, $V_1$, $T_1$ are the initial pressure, volume and temperature, and $P_2$, $V_2$, $T_2$ are the final pressure, volume and temperature.

Step2: Identify the given values

$P_1 = 119\ kPa$, $V_1=7.00\ L$, $T_1 = 330\ K$, $P_2 = 143\ kPa$, $T_2=645\ K$.

Step3: Rearrange the combined - gas law for $V_2$

$V_2=\frac{P_1V_1T_2}{T_1P_2}$.

Step4: Substitute the values into the formula

$V_2=\frac{119\ kPa\times7.00\ L\times645\ K}{330\ K\times143\ kPa}$. First, calculate the numerator: $119\times7.00\times645 = 119\times4515=537285$. Then, calculate the denominator: $330\times143 = 47190$. $V_2=\frac{537285}{47190}=11.4$.

Answer:

$11.4$