for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x +…

for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x + 333.22| = 12.78 can be used to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid.\n\nis the maximum temperature at which nitrogen is a liquid.\nis the minimum temperature at which nitrogen is a liquid.

for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x + 333.22| = 12.78 can be used to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid.\n\nis the maximum temperature at which nitrogen is a liquid.\nis the minimum temperature at which nitrogen is a liquid.

Answer

Explanation:

Step1: Solve the absolute - value equation

The absolute - value equation (|x + 333.22|=12.78) can be split into two cases: Case 1: (x+333.22 = 12.78) Case 2: (x + 333.22=-12.78)

Step2: Solve Case 1

For (x+333.22 = 12.78), subtract 333.22 from both sides: (x=12.78 - 333.22=-320.44)

Step3: Solve Case 2

For (x + 333.22=-12.78), subtract 333.22 from both sides: (x=-12.78-333.22=-346)

Answer:

The maximum temperature is (-320.44^{\circ}F) The minimum temperature is (-346^{\circ}F)