for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x +…

for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x + 333.22| = 12.78 can be used to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid.\n\n is the maximum temperature at which nitrogen is a liquid.\n is the minimum temperature at which nitrogen is a liquid.

for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x + 333.22| = 12.78 can be used to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid.\n\n is the maximum temperature at which nitrogen is a liquid.\n is the minimum temperature at which nitrogen is a liquid.

Answer

Explanation:

Step1: Solve the absolute - value equation

The absolute - value equation (|x + 333.22|=12.78) can be split into two cases. Case 1: (x+333.22 = 12.78) Solve for (x): (x=12.78−333.22=-320.44) Case 2: (x + 333.22=-12.78) Solve for (x): (x=-12.78−333.22=-346)

Step2: Determine maximum and minimum

The two solutions of the equation (|x + 333.22|=12.78) are (x=-320.44) and (x = - 346). Since (-320.44>-346), the maximum temperature is (-320.44^{\circ}F) and the minimum temperature is (-346^{\circ}F).

Answer:

-320.44 -346