for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x +…

for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x + 333.22| = 12.78 can be used to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid. is the maximum temperature at which nitrogen is a liquid. is the minimum temperature at which nitrogen is a liquid.

for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. the equation |x + 333.22| = 12.78 can be used to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid. is the maximum temperature at which nitrogen is a liquid. is the minimum temperature at which nitrogen is a liquid.

Answer

Explanation:

Step1: Understand the absolute - value equation concept

The equation (|x - (- 333.22)|=12.78) represents the distance of (x) from (-333.22) is (12.78). It can be split into two cases: (x-(-333.22)=12.78) and (x - (-333.22)=-12.78).

Step2: Solve for the maximum temperature

For (x-(-333.22)=12.78), simplify the left - hand side to get (x + 333.22=12.78). Then solve for (x): (x=12.78-333.22=-320.44).

Step3: Solve for the minimum temperature

For (x-(-333.22)=-12.78), simplify the left - hand side to get (x + 333.22=-12.78). Then solve for (x): (x=-12.78-333.22=-346).

Answer:

The maximum temperature is (-320.44^{\circ}F) and the minimum temperature is (-346^{\circ}F).