a nuclide of $_{29}^{64}cu$ absorbs a positron. which is the resulting atom?\n$_{29}^{65}cu$\n$_{29}^{63}cu$\…

a nuclide of $_{29}^{64}cu$ absorbs a positron. which is the resulting atom?\n$_{29}^{65}cu$\n$_{29}^{63}cu$\n$_{28}^{64}ni$\n$_{30}^{64}zn$

a nuclide of $_{29}^{64}cu$ absorbs a positron. which is the resulting atom?\n$_{29}^{65}cu$\n$_{29}^{63}cu$\n$_{28}^{64}ni$\n$_{30}^{64}zn$

Answer

Explanation:

Step1: Write the positron - capture equation

Positron has a mass number of 0 and an atomic number of + 1. The general equation for positron capture by a nuclide ${Z}^{A}X$ is ${Z}^{A}X+{+1}^{0}e\rightarrow{Z - 1}^{A}Y$. For ${29}^{64}Cu$, the equation is ${29}^{64}Cu+{+1}^{0}e\rightarrow{28}^{64}Y$.

Step2: Identify the resulting element

The atomic number of the resulting element is 28. The element with atomic number 28 is nickel (Ni). So the resulting atom is $_{28}^{64}Ni$.

Answer:

C. $_{28}^{64}Ni$