an object is launched from a platform. its height (in meters), $x$ seconds after the launch, is modeled by…

an object is launched from a platform. its height (in meters), $x$ seconds after the launch, is modeled by: $h(x)=-5(x - 4)^2+180$. what is the height of the object at the time of launch? meters

an object is launched from a platform. its height (in meters), $x$ seconds after the launch, is modeled by: $h(x)=-5(x - 4)^2+180$. what is the height of the object at the time of launch? meters

Answer

Explanation:

Step1: Identify the time of launch

At the time of launch, $x = 0$.

Step2: Substitute $x = 0$ into the function

Substitute $x=0$ into $h(x)=-5(x - 4)^2+180$. So $h(0)=-5(0 - 4)^2+180$. First, calculate $(0 - 4)^2=(-4)^2 = 16$. Then $-5\times16=-80$. So $h(0)=-80 + 180$.

Step3: Calculate the result

$-80+180 = 100$.

Answer:

100