3. an object of mass 5.0 kg is lifted vertically upward by 2.0 m. assuming the acceleration due to gravity…

3. an object of mass 5.0 kg is lifted vertically upward by 2.0 m. assuming the acceleration due to gravity is 9.8 m/s², how much work is done against gravity?\n\na. 10 j b. 20 j\nc. 49 j d. 98 j

3. an object of mass 5.0 kg is lifted vertically upward by 2.0 m. assuming the acceleration due to gravity is 9.8 m/s², how much work is done against gravity?\n\na. 10 j b. 20 j\nc. 49 j d. 98 j

Answer

Explanation:

Step1: Recall the formula for work done against gravity

The work done against gravity is given by the formula ( W = mgh ), where ( m ) is the mass, ( g ) is the acceleration due to gravity, and ( h ) is the height.

Step2: Substitute the given values into the formula

Given ( m = 5.0 , \text{kg} ), ( g = 9.8 , \text{m/s}^2 ), and ( h = 2.0 , \text{m} ). Substituting these values into the formula: ( W = 5.0 \times 9.8 \times 2.0 )

Step3: Calculate the result

First, calculate ( 5.0 \times 9.8 = 49 ), then multiply by ( 2.0 ): ( 49 \times 2.0 = 98 , \text{J} )

Answer:

D. 98 J