3. is object e or object f more dense? assume the particles are uniformly distributed throughout each…
3. is object e or object f more dense? assume the particles are uniformly distributed throughout each object, and particles with a larger size have a larger mass. explain your reasoning.
Answer
Explanation:
Step1: Recall density formula
Density $\rho=\frac{m}{V}$, where $m$ is mass and $V$ is volume. Given same - volume objects (since they are of the same shape and size), mass determines density.
Step2: Analyze particle mass and number
Object E has larger and more particles. Larger particles have larger mass and more particles mean more total mass. Since $V_E = V_F$ and $m_E>m_F$ (due to larger and more particles in E), from $\rho=\frac{m}{V}$, we have $\rho_E>\rho_F$.
Answer:
Object E is more dense because it has larger and more particles, resulting in a greater mass for the same volume as object F.