ohm’s law practice problems\nusing ohm’s law, solve the following problems. be sure to show all work…

ohm’s law practice problems\nusing ohm’s law, solve the following problems. be sure to show all work. formula: v (voltage)= i (current) x r (resistance)\n1. what is the voltage if a resistance of 25 ω produces a current of 250 amperes?\n2. what is the current produced by a voltage of 240 v through a resistance of 0.2 ω?\n3. what voltage is necessary to produce a current of 200 amperes through a resistance of 100 ω?\n4. what resistance would produce a current of 120 amps from a 6 - v battery?\n5. what is the current produced by a 9 - v battery flowing through a resistance of 200 ω?\n6. what voltage produces a current of 500 amps with a resistance of 50 ω?\n7. what resistance would produce a current of 200 amps with a voltage of 2,000 v?\n8. what is the current produced with a 9 - v battery through a resistance of 100 ω?

Answer

Explanation:

Step1: Recall Ohm's Law

$V = I\times R$, where $V$ is voltage, $I$ is current and $R$ is resistance. We can also derive $I=\frac{V}{R}$ and $R = \frac{V}{I}$.

Step2: Solve problem 1

Given $I = 250$ A and $R=25\ \Omega$. Using $V = I\times R$, we have $V=250\times25 = 6250$ V.

Step3: Solve problem 2

Given $V = 240$ V and $R = 0.2\ \Omega$. Using $I=\frac{V}{R}$, we get $I=\frac{240}{0.2}=1200$ A.

Step4: Solve problem 3

Given $I = 200$ A and $R = 100\ \Omega$. Using $V = I\times R$, we obtain $V=200\times100 = 20000$ V.

Step5: Solve problem 4

Given $V = 6$ V and $I = 120$ A. Using $R=\frac{V}{I}$, we have $R=\frac{6}{120}=0.05\ \Omega$.

Step6: Solve problem 5

Given $V = 9$ V and $R = 200\ \Omega$. Using $I=\frac{V}{R}$, we get $I=\frac{9}{200}=0.045$ A.

Step7: Solve problem 6

Given $I = 500$ A and $R = 50\ \Omega$. Using $V = I\times R$, we obtain $V=500\times50 = 25000$ V.

Step8: Solve problem 7

Given $I = 200$ A and $V = 2000$ V. Using $R=\frac{V}{I}$, we have $R=\frac{2000}{200}=10\ \Omega$.

Step9: Solve problem 8

Given $V = 9$ V and $R = 100\ \Omega$. Using $I=\frac{V}{R}$, we get $I=\frac{9}{100}=0.09$ A.

Answer:

$V = 6250$ V
$I = 1200$ A
$V = 20000$ V
$R = 0.05\ \Omega$
$I = 0.045$ A
$V = 25000$ V
$R = 10\ \Omega$
$I = 0.09$ A