one estimate for the number of protons in betelgeuse is 2.16×10^58. the mass of one proton is about…
one estimate for the number of protons in betelgeuse is 2.16×10^58. the mass of one proton is about 1.67×10^(-27) kg. what is the total mass of all the protons in betelgeuse? which scientist do you agree with?
Answer
Explanation:
Step1: Recall product rule of exponents
When multiplying numbers in scientific - notation (a\times10^{m}) and (b\times10^{n}), the result is ((a\times b)\times10^{m + n}). Here, (a = 2.16), (m = 58), (b=1.67), and (n=-27).
Step2: Multiply the coefficients
Multiply the non - exponential parts: (2.16\times1.67 = 3.6072).
Step3: Add the exponents
Add the exponents of 10: (58+( - 27)=58 - 27 = 31).
Step4: Write the result in scientific notation
The total mass is (3.6072\times10^{31}\text{ kg}).
Answer:
(3.6072\times10^{31}\text{ kg})